- #1

sportsrules

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Q= n*Cp*change in temperature...instead of two moles, would I use 250moles/kg for n to find the heat flow per kilogram, and would i keep the temp change the same from the original temps that i found using the original two moles?

Then, for the work, the adiabatic processes equal

W= n*Cv*change in temp...so do I do the same thing with n again, and keep all the other info the same as what i originally found it to be?

But, for the isobaric process,

W=P*change in V

so i am not quite sure how to incorporate the 250 moles/kg...I could use PV=nRT and find the P in Pa/kg by using 250 moles/kg for n instead of the 2 moles, but then I would be using the original volumes, and wouldn't the voluems change if I changes the pressure? I am very confused...any help would be great!...and also, will the change in Q and the net work for the cycle be equal to each other??