Finding height and time from angle and velocity

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To find the height, distance, and time of a toy rocket launched at a velocity of 30 m/s at a 50-degree angle, the formulas for horizontal distance and height are used. The horizontal distance traveled is calculated as 30 * cos(50°) * t, while the height is given by 30 * sin(50°) * t - (g/2) * t^2, where g is the acceleration due to gravity. It's important to convert the launch angle from degrees to radians for accurate calculations. Ensure that all quantities are expressed in proper units. Understanding these principles can be found in high school mechanics textbooks.
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A toy rocket is launched with a velocity of 30 at an angle of 50 deg. How would I find the height, distance, and time from that? Please help...
 
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Seeing that your question has not been shifted to the homework section, I’ll give you some idea. But the whole thing can be found in any high school mechanics book.

I assume that the toy rocket doesn’t have a propulsion system and is simply given an initial velo.
You have not given the unit of velo, so put the proper units for all the quantities.

If the angle with the horizontal is ‘x’ radians, then after time t,

horizontal dist traveled = 30*(cos x)*t, and

height of the rocket = 30*(sin x)*t –(g/2)*t^2.

Convert 50 degrees to radians.
 

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