Finding how much heat it takes to vaporize

  • Thread starter Skysong12
  • Start date
  • #1
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Homework Statement


How much heat does it take to vaporize 600g of lead that is initially at 34°C?


Homework Equations


heat capacity=1.3X102


The Attempt at a Solution


ΔT = 1750°C - 34°C
= 1716 ° C


Q= m X c X ΔT
= 0.6 X 1.3X102 X 1716
=133,848 J

Am I suppose to factor in the change of state? Is there latent vaporization?
 

Answers and Replies

  • #2
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You've answered your own question. Think about the analogy of turning water to vapor.
 
  • #3
rock.freak667
Homework Helper
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Q= m X c X ΔT
= 0.6 X 1.3X102 X 1716
=133,848 J

Am I suppose to factor in the change of state? Is there latent vaporization?

Yes you are, Q = mcΔT just gives you the heat required to raise the temperature from 34°C to 1716°C.

You just need to use Q=mlvap now and add them.
 
  • #4
PeterO
Homework Helper
2,426
48

Homework Statement


How much heat does it take to vaporize 600g of lead that is initially at 34°C?


Homework Equations


heat capacity=1.3X102


The Attempt at a Solution


ΔT = 1750°C - 34°C
= 1716 ° C


Q= m X c X ΔT
= 0.6 X 1.3X102 X 1716
=133,848 J

Am I suppose to factor in the change of state? Is there latent vaporization?

I not sure lead will even by molten at 34o, so you may have to melt it too. ANd is the heat capacity of solid lead and liquid lead the same?
 

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