Finding I_knot at a certain time in the circuit given

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SUMMARY

The discussion focuses on calculating the current i0(0.1s) in a circuit with resistors R1, R2, R3, R4, R5, and a capacitor C. The equivalent resistance (Req) is determined to be 4.5 kohms, leading to a time constant (Τ) of 2.1375 seconds. The current in the capacitor at t=0.1s is calculated to be 121.64 microA, with the current in resistor R4 being half of that value at 60.8 microA. The term "i naught" is clarified as the notation for initial current.

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Homework Statement


In the network shown, R1=3 kohm, R2=3 kohm, R3=2 kohm, R4=5 kohm, R5=2 kohm, and C=475 microF. Compute i0(0.1s) in microA.

The figure is in the word file attached.


3. The Attempt at a Solution

Time constant is Req*c
Req when circuit is open is Req=r5+(r4*(r3+r2)/ (r4+r3+r2) )
Substituting the values, Req=4.5 kohms
Τ=4.5*10^3*475*10^-6=2.1375
Current in capacitor =12/Req(1-exp(-t/ Τ))
At t=0.1s I = 0.456*12/4.5 *10^-3 =121.64 micro A
Current in R4 = half of current in capacitor=60.8 micro A
 

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This isn't any help for your problem, but i0 is "i nought" or "i naught".

A knot is something used to fasten ropes together or to something.
A knot is also a unit of the speed of a boat in water.
 

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