Finding Initial Angle for a Projectile to Hit a Target 10,000 ft Away

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Homework Help Overview

The problem involves determining two elevation angles for a projectile, specifically a shell, that is fired from ground level with a given muzzle speed to hit a target located 10,000 feet away. The context is rooted in projectile motion and kinematics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the angles and the equations governing projectile motion. There are attempts to manipulate trigonometric identities and equations to find the angles. Some participants express uncertainty about solving for the angles and question the validity of their previous calculations.

Discussion Status

Some participants have made progress in finding one of the angles and have verified it against an answer key. However, there remains confusion regarding the second angle, with one participant indicating a potential mistake in their calculations. Guidance has been offered regarding the equations used, but no consensus has been reached on the correct approach to find the second angle.

Contextual Notes

Participants are working with specific equations related to projectile motion, and there are indications of missing information or assumptions that may affect the calculations. There is also a note about the difficulty of reading some participants' work due to the format in which it was presented.

Marcin H
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Homework Statement

:
[/B]
Find two elevation angles that will enable a shell, fired from

ground level with a muzzle speed of 800 ft/s, to hit a groundlevel

target 10,000 ft away.

Homework Equations


Look at attached picture

The Attempt at a Solution


Look at attached picture

***I get to cos(x)sin(x)=1/4, but I don't think you can solve that for an angle x...
 

Attachments

  • New Doc 1_1.jpg
    New Doc 1_1.jpg
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***UPDATE***

I got one of the angles, and it checks out with the answer key, but how on Earth do I get the angle of 15?

MY WORK:
New Doc 2Page 1.jpg

ANSWER KEY:
ANSWER KEY.png
 
Marcin H said:
***UPDATE***

I got one of the angles, and it checks out with the answer key, but how on Earth do I get the angle of 15?

MY WORK:
View attachment 89769
ANSWER KEY:
View attachment 89770
You have a mistake in your work. As best as I can tell, your answer is close only due to a coincidence.

One of your equations is ##50\sin(\theta) = t## and the other is ##800 \cos(\theta)t = 10000##
Your mistake is in solving for ##\sin(\theta)## in the first equation. It should be ##\sin(\theta) = \frac t {50}##.

BTW, please make an effort to post your work here, rather than as an image. Your work is somewhat difficult to read.
 
S=ut-½at2. (1)
R=vt. (2)

Just eliminate t, and substitute data in the last equation.
 

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