Finding Initial Velocity of a Rock Kicked off a Cliff

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SUMMARY

The problem involves calculating the initial velocity of a rock kicked horizontally off a 40m high cliff, with the sound of the crash heard 3 seconds later. The speed of sound in air is given as 343 m/s. The time taken for the rock to fall and the time for the sound to travel back to the player must be considered separately. By applying the equations of motion, the initial horizontal velocity can be derived from the total time minus the time taken for the sound to return.

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Homework Statement


A soccer player kicks a rock horizontally off a 40m high cliff. If the player hears the sound of the crash 3.00s later, what was the initial speed given to the rock? assume the speed of sound in air is 343m/s.


Homework Equations


Position of Y = -40m
Time = 3s
Position = Ut+.5at^2

The Attempt at a Solution


To find the initial velocity of the rock, I know I must first find the displacement it covered in the x axis. However, I am not sure how to continue. I can use the equation Sx = U*t, but I do not know Sx or U(initial velocity).
How can I derive initial velocity?
 
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Hints: How long did it take for the rock to hit the ground? How long did it take the sound to travel back to the player?
 
Another hint: The rock's initial horizontal does not come into play in determining how long it takes the rock to hit the ground. The initial horizontal velocity only changes how far the rock is from the cliff at the time the rock does hit the ground.
 

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