# Finding initial vertical velocity given acceleration

1. Sep 14, 2015

### freshyy

1. The problem statement, all variables and given/known data
Sam heaves a shot with weight 16-lb straight upward, giving it a constant upward acceleration from rest of 45.4 m/s^2 for a height 65.0 cm . He releases it at height 2.16 m above the ground. You may ignore air resistance.

Q-What is the speed of the shot when he releases it?

2. Relevant equations:
Equations I believe I can use are
V=initial V +at or
V^2=initial V^2 +2a(x-initial x)

3. The attempt at a solution
Since the final velocity would be zero when it is at the highest point i got
0=initial V^2 +2(45.4m/s^2)(-.65m)
I would have V ^2=59.02
then V=7.68m/s
but this says it is wrong when i check my answer.

2. Sep 14, 2015

### Staff: Mentor

The final velocity is the velocity when he releases it--that's not zero. It starts at zero.

Nonetheless, the equation is correct and so is your answer. Are you sure you are posting the exact problem?