Finding initial wavelength of photo given angle of deflection

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Homework Help Overview

The problem involves finding the initial wavelength of a photon that undergoes Compton scattering, losing half its energy and emerging at a specific angle. The context is within the realm of quantum mechanics and photon interactions with electrons.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Compton's formula and relates energy to wavelength but expresses uncertainty due to missing initial energy information. Some participants question the implications of the angle and energy loss on the wavelength, while others suggest considering relationships between energy, frequency, and wavelength.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some guidance has been offered regarding the relationships between energy and wavelength, but no consensus has been reached on a complete solution.

Contextual Notes

The original poster notes a lack of initial energy information, which is crucial for determining the initial wavelength. There is also a mention of potential moderator concerns regarding the discussion content.

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Homework Statement




Find the initial wavelength of a photon that loses half its energy when it Compton-scatters from an electron and emerges at 90∘ to its initial direction of motion.



The Attempt at a Solution



Ei = Ef +KE
Ei = 0.5Ei + KE

Using compton's formula for scattering of photon:

Δλ = λf - λi = 2.42444x10-12 m

λi = λf - 2.42444x10-12 m

pretty much stuck. If I know the initia energy, find the initial wavelength would be a breeze but I don't have that information. Or if I know the numerical value of KE, I can by KE = 0.5Ei, find initial wavelength.
 
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What did you do with the 90 degrees information ?

[edit] Oops, already used. Good. So what does halving the energy do to the wavelength of a photon ?
 
Last edited:
BvU said:
What did you do with the 90 degrees information ?

[edit] Oops, already used. Good. So what does halving the energy do to the wavelength of a photon ?

not really sure if I will incur the wrath of the moderators but I already solved it.

The key was introducing E=mc2 and E = hf
one learnts that f could be found.
f is also equals to c/λ and with this λ could be found.
 
Well done. No reasons for our good moderating spirits to get excited at all !
 

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