Finding instantaneous velocity of objects in projectile motion

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SUMMARY

The discussion focuses on calculating the instantaneous velocity of an object in projectile motion with an initial speed of 8 m/s and no air resistance at a time of 3 seconds. The components of displacement are given as dx=24 and dy=44. To find the instantaneous velocity, participants suggest using kinematic equations, specifically s=ut+(1/2)at^2 for vertical motion, and the formula v=d/t for horizontal motion. The correct approach involves determining the initial vertical velocity and calculating both horizontal and vertical components at the specified time.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Ability to decompose vectors into horizontal and vertical components
  • Familiarity with basic algebra for solving equations
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  • Study the derivation and application of kinematic equations in projectile motion
  • Learn how to calculate the trajectory of projectiles using initial velocity and angle
  • Explore the effects of air resistance on projectile motion
  • Practice solving problems involving instantaneous velocity in various motion scenarios
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Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for effective problem-solving strategies in kinematics.

Suzan
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Homework Statement


No air resitance
Initial speed 8 m/s
inst. time at 3 s

Find instantaneous velocity at 3s.

Components of displacement:
dx= 24
dy= 44


Homework Equations



d=v1t+(1/2)a(t)^2 or other kinematics equations

The Attempt at a Solution



I tried to find the components of the velocity using the components of the displacement (d/t=v). But both my answer and angle of direction were wrong. How do i do this?
 
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Suzan said:

Homework Statement


No air resitance
Initial speed 8 m/s
inst. time at 3 s

Find instantaneous velocity at 3s.

Components of displacement:
dx= 24
dy= 44

So dx and dy are those values at t=3?
If so consider Vertical motion:
[itex]s=ut+\frac{1}{2}at^2[/itex]

where u is the initial vertical velocity. Sub t=3 in there and get u. and well you know how to get the horizontal component (v=d/t as you stated before)
 

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