Finding Kip/Ft: Homework Solutions & Explanations

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Homework Help Overview

The discussion revolves around understanding a triangularly distributed load represented in kip/ft, specifically focusing on how to interpret the load values along a beam and the calculation of total load using area integration. Participants are trying to clarify the relationship between the graphical representation of the load and its actual distribution.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are exploring how to interpret the load values, questioning the meaning of the arrows indicating load variations, and discussing the calculation of total load through integration. There is also inquiry into the location of the center of gravity of the triangular load distribution.

Discussion Status

Some participants have provided clarifications regarding the total load and its representation, while others are still grappling with the implications of the graphical representation versus the actual load distribution. There is an ongoing exploration of the concepts without a clear consensus yet.

Contextual Notes

There is a mix-up in units and interpretations of the load distribution, which participants are attempting to resolve. The original poster expresses confusion regarding the calculations and the reasoning behind certain values presented in the answers.

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Homework Statement



Number 1-5 from here http://www.slideshare.net/hotman1991/met-302-chapter-01

How do I deal with the 1.5 kip/ft? Am I right to think that the smaller arrows to the left mean that the kip/ft there is less than 1.5kip/ft? How can I find kip/ft at a given point along the horizontal axis?
* I know that the answers are given, however I do not understand it.

Homework Equations



Possibly A = 1/2(b*h) = 1/2(12)(1.5) = 9 kips

EDIT: I also found the same 9kip/ft through ∫(1.5x/12)dx from 0 to 12.

The Attempt at a Solution



The answers use area to get total (?) kips. I sort of understand why they would do that, something like integrating from 0-12 ft. However, I do not understand how they found 9kips at 4ft from B, or why they put the 9 kips there at 4ft.
 
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The triangularly distributed load is 0 kip/ft on the left side and 1.5 kip/ft on the right side.

The total load is not 9 kip/ft, it's 9 kips, period.

What is the location of the center of gravity of a right triangle?
 
SteamKing said:
The triangularly distributed load is 0 kip/ft on the left side and 1.5 kip/ft on the right side.

The total load is not 9 kip/ft, it's 9 kips, period.

What is the location of the center of gravity of a right triangle?

Yes, sorry about the units mix up.

Ah, I see what you mean. So we take it as if the 9 kips is at the center of gravity... Do we ignore the vertical part of the center of gravity? The answer seems to do so (both equations and equations don't take it into account).
 
The load is along the length of the beam. You are confusing the graphical representation of a distributed load with how the load is actually distributed. In other words, the vertical component doesn't exist.
 
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SteamKing said:
The load is along the length of the beam. You are confusing the graphical representation of a distributed load with how the load is actually distributed. In other words, the vertical component doesn't exist.

Whoops. Thanks for reminding me. I appreciate all of your help.
 

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