1. The problem statement, all variables and given/known data The steel column is used to support the symmetric loads from two floors of an officer building. Determine the loads P1 and P2 if A moves downward 0.12 in and B moves downward 0.09 in under the applied loading. The steel column has a cross-sectional area of 23.4 in2. Length of A from the ground = 22ft Length of B from the ground = 12 ft 2. Relevant equations δ=(Force*Length)/(Area*Modulus of Elasticity) Force = (δ*Area*Modulus of Elasticity)/(Length) 3. The attempt at a solution Force of A = (-0.12in*23.4in2*30000Kpsi)/(264in) = -319Kip Force of B = (-0.09in*23.4in2*30000KPsi)/(144in) = -438.75 Kip The correct answer is Force of A = -90 kip and Force of B = -130 Kip What did I do wrong?