(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The steel column is used to support the symmetric loads from two floors of an officer building. Determine the loads P_{1}and P_{2}if A moves downward 0.12 in and B moves downward 0.09 in under the applied loading. The steel column has a cross-sectional area of 23.4 in^{2}.

Length of A from the ground = 22ft

Length of B from the ground = 12 ft

2. Relevant equations

δ=(Force*Length)/(Area*Modulus of Elasticity)

Force = (δ*Area*Modulus of Elasticity)/(Length)

3. The attempt at a solution

Force of A = (-0.12in*23.4in^{2}*30000Kpsi)/(264in) = -319Kip

Force of B = (-0.09in*23.4in^{2}*30000KPsi)/(144in) = -438.75 Kip

The correct answer is Force of A = -90 kip and Force of B = -130 Kip

What did I do wrong?

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# Homework Help: How to force forces of the floors

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