How Do You Calculate Forces in Truss Members IK, JL, and JM?

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Homework Help Overview

The problem involves calculating the forces in specific members of a barrel vault truss under load. The original poster provides details about the truss dimensions and initial equations based on equilibrium conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use free body diagrams and equilibrium equations to find the forces in members IK, JL, and JM. Some participants suggest using the method of joints and question the implications of the roller support in the truss setup.

Discussion Status

The discussion is ongoing, with participants offering different approaches to tackle the problem. There is a suggestion to cut a section through the truss to simplify the analysis, and some participants express uncertainty about specific angles and the implications of the support conditions.

Contextual Notes

Participants note the presence of unknowns and the need for additional information, such as reference angles, to proceed with the calculations. The original poster indicates a struggle to move forward after establishing initial equations.

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[PLEASE HELP!] Forces in members of a truss

Homework Statement



A barrel vault truss is loaded as shown. Knowing that the length of the bottom chords DF, FH, ..., and QS is 3 ft, determine the force is members IK, JL, and JM.

http://img68.imageshack.us/img68/4817/fyjfhjfgjhfghgx8.jpg

Homework Equations



Sum of y-components
\sum F_{x} = 0

x-components
\sum F_{y} = 0

Moment
\sum M = 0

The Attempt at a Solution



First I did a free body diagram of the entire truss, which gave me three unknowns tosolve for first.

http://img392.imageshack.us/img392/9493/fyjfhjfgjhfgh1ur3.jpg

\sum F_{x} = 0:
A_{x} = 0

\sum F_{y} = 0:
A_{x} = (1+1.5+1.5+1+1.5+1.5+1) = A_{y} + V_{y}
9 kips = A_{y} + V_{y} ---- (1)

Solving for Moment about A
\sum M_{a} = 0:
V_{y} (18) = (1.5)(3) + (1.5)(6) + (1)(9) + (1.5)(12) + (1.5)(15) + (1)(18) =
V_{y} = 4.5 kips ----- (2)

Then plugging equation (2) into equation (1) I get
A_{y} = 4.5

Then I get stuck. I know I need to pass a section through the truss so I can get two portions, with each including the desired members I am solving for. Then I just draw a FBD and solve for no more than three unknowns.
 
Last edited by a moderator:
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You can get IK pretty quick using the method of joints. Beyond that, I don't like that roller support at the bottom corner. Nonetheless, try then cutting a section from IK through JM.
 
Last edited:


have you considered this.. do you know the reference angle?(i know it, i think you know it too)
Once you figure out IK, and you cut through as PhanthomJay says, you now have 3 unknowns and 3 equations..in other words, solvable.
 

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    IK.JPG
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help... anyone can help to settle this problem?
 

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