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Calculating Pressure Exerted on A Gasoline Column

  1. Jun 14, 2015 #1
    I am requesting for another set of eyes to double check my work, I believe my answer is correct but I am not sure. I also do not understand why 0.75 is the specific gravity of gasoline in this equation when it actually can range from 0.71-0.77

    1. The problem statement, all variables and given/known data


    Calculate the pressure exerted on a 26-ft column filled with 13 ft. of gasoline. The vapor pressure of gasoline at 100°F is 12 psi.

    2. Relevant equations

    Height x 0.433 x specific gravity (according to the text book) = pressure.


    3. The attempt at a solution

    26 ft. x 0.433 x 0.75 = 8.4435 psi + 12 psi = 20.4435 psi
     
  2. jcsd
  3. Jun 15, 2015 #2

    DEvens

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    Education Advisor
    Gold Member

    Ohhhhh.... Magic numbers make my stomach hurt.

    Presumably the 0.433 is a unit converter that tells you the pressure, in psi, of 1 foot of water. It seems about right. If that is what the text tells you, then so good so far. Except our arithmetic seems a bit wonky. Check your multiplication please.

    The column is 26 feet, and you have used that number in your answer. But the column is 26 feet high, not the gas. What if there was only a tenth of an inch of gas in the column? What would the pressure be then?

    For completeness, your equation should include the vapor pressure, since you included that later.
     
  4. Jun 15, 2015 #3
    Is the column open to the atmosphere? If not, anything other than gasoline vapor above the liquid level? Is it asking for the pressure at the bottom of the column (probably, but not stated)? As implied above, your answer is not correct.
     
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