Finding Length and Area of Tungsten Wire Resistor

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SUMMARY

The discussion focuses on calculating the length and cross-sectional area of a tungsten wire resistor with a target resistance of 20Ω. The resistivity of tungsten is given as 4.9 x 10-6 Ωcm. The resistance formula used is r = ρl/A, where r is resistance, ρ is resistivity, l is length, and A is cross-sectional area. Participants suggest using standard wire gauges (AWG 16-26) to determine feasible cross-sectional areas, which can then be used to calculate the corresponding lengths.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the formula r = ρl/A
  • Knowledge of tungsten's resistivity (4.9 x 10-6 Ωcm)
  • Basic understanding of wire gauge standards (AWG)
NEXT STEPS
  • Research standard wire gauges and their corresponding cross-sectional areas
  • Learn how to manipulate the resistance formula r = ρl/A for different variables
  • Explore the properties of tungsten and its applications in resistors
  • Investigate practical methods for constructing homemade wire resistors
USEFUL FOR

Students in electrical engineering, hobbyists building electronic circuits, and anyone interested in understanding the principles of resistance in materials.

do you think that this is as level or a2 level


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Homework Statement


the actual question is
the resitivity of tungsten metal is 4.9x10to the power of -6 Ωcm. choose appropriate values for length and cross-sectional area for a home made wire resistor of resitstance 20Ω

Homework Equations



r=pl/a
r-resistance
a-cross sectional area in m squared
l- length of wire in meters
p is resistivity of the material in ohm(meters)

The Attempt at a Solution


i don't even know wher to start all i know is that i need to find L and A but i only know p's value, please help,

 
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Hello, and welcome to PF. I can't answer the poll because I don't know what it is asking. I don't, for future reference, think this problem belongs in "advanced physics."

The reason you can't "solve" this problem is because you are supposed to come up with the values yourself. You could look up the standard gauges of wire (most people use 16-26awg at the very most/least) to get a range of possible area, and from there solve for length..
 

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