Finding length of vector with unknown variable

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The discussion revolves around finding the length of a vector V = (-2/3, b, 16/7) with an unknown variable b. The length is calculated using the formula Sqrt(a^2 + b^2 + c^2), leading to the expression Sqrt(50/21 + b^2). Participants debate whether it is possible to determine the value of b without a specified length for the vector, with some suggesting that the minimum value of b^2 can be zero. Ultimately, it is clarified that if b can be any real number, the smallest possible value of b^2 is indeed zero, simplifying the problem significantly. The conversation highlights the importance of understanding the implications of variable constraints in vector length calculations.
cathal84
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Finding length of vector with unknown variable.
Purely for study purposes.
Find the smallest possible length of the vector →v .
Let vector V = (-2/3,b,16/7)
Equation for finding length of vector : Sqrt(a^2+b^2+c^2)Question would be quite straight forward had there been no unknown variable but since there is i am quite stuck.
when i work out the equation as per normal i get Sqrt(50/21+b^2)
Is it possible to work out the unknown variable in this question? I don't think it is but please correct me if I'm wrong
 
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cathal84 said:
Find the smallest possible length of the vector →v .
That is when the sqrt(a^2+b^2+c^2) is minimal.
 
cathal84 said:
i work out the equation as per normal i get Sqrt(50/21+b^2)
I'd check that again...
 
cathal84 said:
Is it possible to work out the unknown variable in this question? I don't think it is but please correct me if I'm wrong
Yes, you can thus you are wrong :)
 
Well, we had these questions for a level. But it doesent make sense to me.

Dont you mean if length of vector x is Y units, and vector X = (-2/3,b,16/7), thus find the value of b.

Otherwise how..:sorry: You must have been given a length for the vector, and then told to find the unknown component.? unless length of vector can also be zero.
 
Bipolar Demon said:
Well, we had these questions for a level. But it doesent make sense to me.
Dont you mean if length of vector x is Y units, and vector X = (-2/3,b,16/7), thus find the value of b.
Otherwise how..:sorry: You must have been given a length for the vector, and then told to find the unknown component.?
It does make sense, hwever its strange how it doesn't matter what a and c are :)
 
Replusz said:
It does make sense, hwever its strange how it doesn't matter what a and c are :)

\

edit: got it. sorry, long time
 
Last edited:
Only if a=b=c=0 then the length l=sqrt(0)=0, yes. But this wasnt the question
 
Replusz said:
Yes, you can thus you are wrong :)
thanks for your reply, since it is possible to find the unknown variable, could you possibly point me in the right direction on how to do so?
 
  • #10
the length is sqrt(a^2+b^2+c^2)=sqrt(somehtin+b^2)
something is a number, like 2 or 5, or ... You miscalculated it though. It is a^2+c^2
Now a root is minimal if the thing inseide it is minmal. So b^2 + something is minimal. So b^2 is minimal
So now, what is b?
 
  • #11
Replusz said:
the length is sqrt(a^2+b^2+c^2)=sqrt(somehtin+b^2)
something is a number, like 2 or 5, or ... You miscalculated it though. It is a^2+c^2
Now a root is minimal if the thing inseide it is minmal. So b^2 + something is minimal. So b^2 is minimal
So now, what is b?
still struggling with the question, i don't believe i have come across the concept of a minimal root and can't seem to find it in my textbook, is it possible you could explain further? thanks
 
  • #12
cathal84 said:
still struggling with the question, i don't believe i have come across the concept of a minimal root and can't seem to find it in my textbook, is it possible you could explain further? thanks

You are over-thinking the problem. If ##b## is allowed to be any real number whatsoever, what is the smallest possible value of ##b^2##?
 
  • #13
Ray Vickson said:
You are over-thinking the problem. If ##b## is allowed to be any real number whatsoever, what is the smallest possible value of ##b^2##?
Ah right, that makes a lot more senses haha thanks Ray and Replusz for your contribution.
 

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