Finding Linear Transformation that will remove cross product term.

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Homework Help Overview

The discussion revolves around finding a linear transformation that will eliminate the cross product term from a given quadratic form involving variables x1, x2, and x3. The quadratic form is expressed as 2x1² + 4x2² + 5x3² - 4x1x3, and the goal is to express the resulting form in terms of new variables u1, u2, and u3.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to identify a matrix A that represents the quadratic form and consider diagonalization as a potential approach. Some participants question how to derive the matrix A when it is not provided, while others suggest starting with simpler cases, such as a 2x2 example, to understand the generalization to a 3x3 case.

Discussion Status

The discussion is ongoing, with some participants exploring different methods to approach the problem, including diagonalization and matrix representation. There is acknowledgment of the utility of simpler examples to build understanding, but no consensus has been reached on a definitive method for the original problem.

Contextual Notes

Participants note that the problem may involve assumptions about the matrix structure and the nature of the quadratic form. There is also mention of a previous part of the problem providing a matrix, which influenced one participant's approach.

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Homework Statement



Find a linear transofmration from X={x1,x2,x3} to U={u1,u2,u3} which will remove the cross product term in the quadratic form of equation 2X12+4X22+5X32-4X1X3
and thus write the resulting quadratic form in u1,u2,u3.

Homework Equations





The Attempt at a Solution


No idea at the moment. I presume that the 4x1x3 term is the term that I need to have disappear, but other than that, I can sure use some help. Thanks
 
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Let
[tex]\vec{x}=\begin{pmatrix}x_1\\x_2\\x_3\end{pmatrix}[/tex]
Find the matrix A such that
[tex]\vec{x}^\mathrm{T} A \vec{x} = 2x_1^2+4x_2^2+5x_3^2-4x_1x_3[/tex]
You want to diagonalize this matrix.
 
vela said:
Let
[tex]\vec{x}=\begin{pmatrix}x_1\\x_2\\x_3\end{pmatrix}[/tex]
Find the matrix A such that
[tex]\vec{x}^\mathrm{T} A \vec{x} = 2x_1^2+4x_2^2+5x_3^2-4x_1x_3[/tex]
You want to diagonalize this matrix.

Hello vela.
Thanks for the reply!
The problem actually gave a matrix for a previous part so just diagonalizing it solved the problem fairly easily. However, if there are no given matrix, how would I find the matrix?
 
Try a 2x2 example. Calculate
[tex]\begin{pmatrix} x & y \end{pmatrix}\begin{pmatrix} a & b \\ c & d \end{pmatrix}\begin{pmatrix} x \\ y \end{pmatrix}[/tex]
Compare it to [itex]Ax^2 + Bxy + Cy^2[/itex]. What values would you choose for a, b, c, and d to get the coefficients A, B, and C? Note that you're shooting for a symmetric matrix. Can you generalize this to the 3x3 case?
 
vela said:
Try a 2x2 example. Calculate
[tex]\begin{pmatrix} x & y \end{pmatrix}\begin{pmatrix} a & b \\ c & d \end{pmatrix}\begin{pmatrix} x \\ y \end{pmatrix}[/tex]
Compare it to [itex]Ax^2 + Bxy + Cy^2[/itex]. What values would you choose for a, b, c, and d to get the coefficients A, B, and C? Note that you're shooting for a symmetric matrix. Can you generalize this to the 3x3 case?

I see. I understood it now! Thanks a lot for your help :)
 

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