Finding magnitude of two charge given midpoint

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SUMMARY

The discussion focuses on calculating the magnitudes of two positive point charges, A and B, which are 6 meters apart, given the electric field intensity of 5 N/C at the midpoint and a potential of 45V. The participant initially used the equation E = kQ/r² to find a charge value of 5x10-9C, but was confused by the answer key indicating that charge A is twice the magnitude of charge B. The correct approach involves recognizing that both charges contribute to the electric field and potential at point C, necessitating a system of equations to solve for the individual charges.

PREREQUISITES
  • Understanding of electric field concepts and equations, specifically E = kQ/r²
  • Knowledge of electric potential and its relationship with point charges
  • Familiarity with basic algebra and solving systems of equations
  • Concept of superposition in electric fields
NEXT STEPS
  • Study the principle of superposition in electric fields and potentials
  • Learn how to set up and solve systems of equations for multiple point charges
  • Explore the relationship between electric field intensity and charge magnitude
  • Review the concepts of electric potential energy and its calculations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone looking to deepen their understanding of electric fields and potentials in the context of point charges.

paulie
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Homework Statement


Two positive point charges, A and B are 6m apart. The electric field intensity at point C, midway between the two charges is 5 N/C directed towards B and the potential at the same point is 45V. Find the magnitude of A and the magnitude of B.

Homework Equations


E = kQ/r2

The Attempt at a Solution


From what I visualize it:

(+A)<---3m--->(-C)<---3m--->(+B)

Using E = kQ/r2 where Q=Er2/k

Q = (5 N/C)(3 m)2 / (9x109 Nm2/C2) = 5x10-9C

which is the answer for A and B I suppose? But the answer key tells me that the answer in A is twice the B. How come? I'm quite confuse on how this works.
 
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paulie said:

Homework Statement


Two positive point charges, A and B are 6m apart. The electric field intensity at point C, midway between the two charges is 5 N/C directed towards B and the potential at the same point is 45V. Find the magnitude of A and the magnitude of B.

Homework Equations


E = kQ/r2

The Attempt at a Solution


From what I visualize it:

(+A)<---3m--->(-C)<---3m--->(+B)

Using E = kQ/r2 where Q=Er2/k

Q = (5 N/C)(3 m)2 / (9x109 Nm2/C2) = 5x10-9C

which is the answer for A and B I suppose? But the answer key tells me that the answer in A is twice the B. How come? I'm quite confuse on how this works.
The equation you applied is valid for the electric field of a single point charge. You have two charges, QA and QB, both contributing to the electric field and to the potential at point C.
 

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