Finding magnitude of two charge given midpoint

paulie
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Homework Statement


Two positive point charges, A and B are 6m apart. The electric field intensity at point C, midway between the two charges is 5 N/C directed towards B and the potential at the same point is 45V. Find the magnitude of A and the magnitude of B.

Homework Equations


E = kQ/r2

The Attempt at a Solution


From what I visualize it:

(+A)<---3m--->(-C)<---3m--->(+B)

Using E = kQ/r2 where Q=Er2/k

Q = (5 N/C)(3 m)2 / (9x109 Nm2/C2) = 5x10-9C

which is the answer for A and B I suppose? But the answer key tells me that the answer in A is twice the B. How come? I'm quite confuse on how this works.
 
paulie said:

Homework Statement


Two positive point charges, A and B are 6m apart. The electric field intensity at point C, midway between the two charges is 5 N/C directed towards B and the potential at the same point is 45V. Find the magnitude of A and the magnitude of B.

Homework Equations


E = kQ/r2

The Attempt at a Solution


From what I visualize it:

(+A)<---3m--->(-C)<---3m--->(+B)

Using E = kQ/r2 where Q=Er2/k

Q = (5 N/C)(3 m)2 / (9x109 Nm2/C2) = 5x10-9C

which is the answer for A and B I suppose? But the answer key tells me that the answer in A is twice the B. How come? I'm quite confuse on how this works.
The equation you applied is valid for the electric field of a single point charge. You have two charges, QA and QB, both contributing to the electric field and to the potential at point C.
 

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