1. The problem statement, all variables and given/known data A girl of mass mg = 52 kg is pulling a sled up a slippery slope. The coefficient of friction between the girl's boots and the slope is µs = 0.157; the friction between the sled and the slope is negligible. The girl can pull the sled up the slope with a ≤ a max = 0.015 m/s2 before she begins to slip. Assume the rope connecting the girl to the sled is kept parallel to the slope at all times. The angle of the slope is θ = 8°. 2. Relevant equations (All below) 3. The attempt at a solution Net Force on girl: T=mg(a+gsin(8)+Us(gcos(8)) T=52(((0.015+(9.8sin8)+(0.157)(9.8)(cos8)) T=150.9N Net Force on sled: ma=T-mgsin8 m(a+gsin8)=T m= (150.9)/(0.015+9.8sin8) m= 109.5 kg It's wrong. Anything I did wrong? Appreciate any help!