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Newton's Law: sliding down a slope

  1. Aug 6, 2013 #1
    A snow sled, with total mass 80.0 kg, is lowered at constant speed down a slope of angle 60.0° with respect to the horizontal, for a distance d = 14.0 m. The coefficient of kinetic friction between the sled and the snow is 0.290.

    Note: g = 9.80 m s–2.

    1. What is the work done by the friction force when the sled slides a distance d down the inclined slope?



    Equations tried using:
    Fnet = F1 + F2 + F3
    Ffr = µf(mgcos theta)
    Fnet = Wsin theta - F friction



    i found the Fw to be 541N and the Ff to be 124N but then i seem to get lost on how to get tension force to get the net work done by friction, i used the formula Fnet = Fw-T-Ff = 0
    Fw - Ff = T = 416N then got stuck
     
  2. jcsd
  3. Aug 6, 2013 #2
    I do not see an equation for work - which is what you are supposed to find. What is it?
     
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