Finding maximum in interference pattern

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In a three-slit interference system, the first minimum occurs at an angular position of 5.00°, prompting the need to find the first maximum. The relevant equation is dsinθ = mλ/N, where the maximum corresponds to bright regions and the minimum to dark regions. The correct calculation involves using sinX = 3sin5°, leading to an angular position for the first maximum of approximately 1.66°. A common mistake noted was dividing by three instead of multiplying, which affects the result. Clarification on the definitions of maximum and minimum intensities was also provided.
Les talons
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Homework Statement


In a three-slit system, the first minimum occurs at an angular position of 5.00°. Where is the first maximum?

Homework Equations


dsinθ = mλ/N

The Attempt at a Solution


dsin5° = λ
dsinX = λ/3
sinX = 3sin5°
X = 1.66°

I'm not sure if this is the right equation to find the first maximum in the interference pattern. Also, is the maximum the bright region and the minimum the dark region? Thanks all.
 
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I get 15,2o when I solve for X?
But your approach is correct, yes.
And yes, the maximum (intensity) is the bright region
and the minimum (intensity of light) is the dark region.
 
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Likes Les talons
Oh geez, what a silly mistake of dividing by three instead of multiplying by three... :confused: Thanks for the feedback.
 
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