Finding Net Force with the Coefficient of Friction

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SUMMARY

The discussion focuses on calculating the net force acting on a 51 kg child sliding down a 42-degree incline with a coefficient of friction of 0.10. The normal force (Fn) is determined to be 379 N using the equation Fn = mgcos(θ). The frictional force is calculated as 38 N using Fk = μFn. The net force acting on the child can be derived by considering both the gravitational component down the slide and the opposing frictional force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with trigonometric functions in physics
  • Knowledge of frictional force calculations
  • Ability to apply free-body diagrams
NEXT STEPS
  • Study the concept of net force in inclined planes
  • Learn about the effects of different coefficients of friction on motion
  • Explore the use of free-body diagrams for complex motion scenarios
  • Investigate the relationship between mass, acceleration, and net force
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of motion on inclined planes, particularly in relation to forces and friction.

triamanda
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Homework Statement


A 51kg child goes down a 42 degree slide. What is the normal force on him? If the coefficient of friction is .10, what is the net force on him? How far down does he slide before reaching 2.5 m/s?

Homework Equations



Fk = μFn
F = ma

The Attempt at a Solution



Fn = 51gcos(42)
= 379 N

I have no idea what to do to find the net force.
 
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the component of the child's weights acts down the plane. Friction acts up the plane.

Also for a normal force N, the frictional force is given by μN.

Can you find the resultant force now?
 
I believe so:
.10(379) = 38 N

Thanks!
 

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