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Introductory Physics Homework Help
Question: How do I account for the wire below the loop when finding net torque?
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[QUOTE="nuagerose, post: 4537075, member: 487224"] [h2]Homework Statement [/h2] [PLAIN]http://ezto.mhecloud.mcgraw-hill.com/13252699450881445581.tp4?REQUEST=SHOWmedia&media=ch28q44a.jpg[/PLAIN] A long, straight wire has a 11.1‐A current flowing in the positive x -direction, as shown in the figure. Close to the wire is a square loop of copper wire that carries a 1.65‐A current in the direction shown. The near side of the loop is d=50.7cm away from the wire. The length of each side of the square is a=1.31m . Question: Find the net torque on the loop. [h2]Homework Equations[/h2] Torque = n*I*A*B*sin θ [h2]The Attempt at a Solution[/h2] n, which is the number of windings is 1. A is the area that the loop encompasses. However, since there is a wire below the loop with current running through it, how do I account for that in the values of I and B and θ? [/QUOTE]
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Introductory Physics Homework Help
Question: How do I account for the wire below the loop when finding net torque?
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