Finding Number of Moles with Ideal Gas Equation

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SUMMARY

The discussion centers on calculating the number of moles using the Ideal Gas Equation, represented as n = PV/RT. The user initially expresses confusion regarding unit conversions, specifically questioning the presence of mol^-1 in the formula. Clarifications provided confirm that using 1 Pa * 1 m^3 in conjunction with the gas constant R (8.314 JK^-1 mol^-1) and temperature in Kelvin yields the correct unit of moles (n). The formula is validated, ensuring that the units align correctly to produce the desired result.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Familiarity with SI units, particularly pressure (Pascal), volume (cubic meters), and temperature (Kelvin)
  • Knowledge of the gas constant (R = 8.314 JK^-1 mol^-1)
  • Basic algebra for unit conversion and manipulation
NEXT STEPS
  • Study the Ideal Gas Law applications in real-world scenarios
  • Learn about unit conversions in thermodynamics
  • Explore the implications of the gas constant R in various conditions
  • Investigate the relationship between pressure, volume, and temperature in different gas behaviors
USEFUL FOR

Chemistry students, physicists, and anyone involved in thermodynamics or gas calculations will benefit from this discussion.

jimmy42
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I want to find the number of moles and I have the ideal gas equation as :

n = PV/RT

However I think I'm using the wrong units to find it, I want the answers in moles.

n = (1 Pa * 1 m^3) /(8.314 JK^-1 mol^-1 * 1K)

so would this give the answer x mol^-1??

I can't see how that would be.

Thanks.
 
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Where's the mol^-1 in the formula? What's

\frac{1}{a^{-1}} = ?
 
Doesn't that just equal a? Not sure how that helps?

Isn't 1Pa * 1m^3 = 1 Pa m^3??
 
n gives the number of moles and you are using the right units.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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