Finding Omega and Zeta from a Magnitude and Phase Plot

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SUMMARY

The discussion focuses on estimating the natural frequency (ωn) and damping ratio (ζ) from the magnitude and phase plot of an atomic force microscope (AFM). The -3dB bandwidth is identified as a crucial factor for determining the quality factor (Q), which is inversely related to ζ. Participants confirm that for an underdamped second-order system, ωn can be approximated by the frequency at which the response peaks, with a suggested value of 72.7 kHz for the AFM cantilever. Additionally, a relationship exists between the peak frequency and ζ that can provide more precise calculations.

PREREQUISITES
  • Understanding of second-order system dynamics
  • Familiarity with magnitude and phase plots
  • Knowledge of quality factor (Q) and its relationship to damping ratio (ζ)
  • Basic principles of atomic force microscopy (AFM)
NEXT STEPS
  • Study the calculation of natural frequency (ωn) in second-order systems
  • Research the significance of -3dB bandwidth in system analysis
  • Explore the relationship between quality factor (Q) and damping ratio (ζ)
  • Learn about phase response in higher-order systems and their implications
USEFUL FOR

Engineers, physicists, and researchers involved in control systems, particularly those working with atomic force microscopy and dynamic system analysis.

Loppyfoot
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Homework Statement


I've been asked to estimate ωn and ζ from the magnitude and phase plot of an atomic force microscope. The magnitude and phase plot is attached.

Does anyone know how to solve for these values?
W0nWUxM.png
 
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The -3dB bandwidth will give you Q, and Q is related to ζ
 
NascentOxygen said:
The -3dB bandwidth will give you Q, and Q is related to ζ

Could you elaborate? Where does this -3dB bandwidth come from? Is Q inversely related to the damping ratio, ζ?

Thanks for your help.
 
I suggest that you try a google search for the details.
 
I was able to calculate the value for the damping ratio; but I am having trouble finding the value of the natural frequency. Any ideas on how to solve for the natural frequency?
 
Loppyfoot said:
I was able to calculate the value for the damping ratio; but I am having trouble finding the value of the natural frequency. Any ideas on how to solve for the natural frequency?
Because the system is so underdamped, the natural frequency is practically equal to the frequency where the response peaks. (Which looks suspiciously co-incident with that 90° crossing on the phase plot, though off-hand I can't say that's right.) I suppose you are approximating this to a second-order system?
 
NascentOxygen said:
Because the system is so underdamped, the natural frequency is practically equal to the frequency where the response peaks. (Which looks suspiciously co-incident with that 90° crossing on the phase plot, though off-hand I can't say that's right.) I suppose you are approximating this to a second-order system?

Yes, I am assuming that the AFM cantilever is being modeled as a second order system. With the cantilever tune, the phase curve is set to 90° of the resonant frequency. So would I be close enough in estimating that the natural frequency is 72.7 kHz?
 
Loppyfoot said:
Yes, I am assuming that the AFM cantilever is being modeled as a second order system. With the cantilever tune, the phase curve is set to 90° of the resonant frequency. So would I be close enough in estimating that the natural frequency is 72.7 kHz?
Most likely. Though there is an equation relating frequency at the peak and ζ back to Ѡn if you really wanted to be precise.

The phase in a true second order system approaches 180° at infinity, so your system seems to have some higher order term because it apparently goes beyond 220°.
 

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