Finding parallel or in-series resistors

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The discussion clarifies that the 45 ohm and 15 ohm resistors are in parallel due to their common connection points, despite any confusion regarding their physical arrangement in the circuit diagram. The key point is that the connecting wires are considered to have zero resistance, allowing the junctions to function as single points. The arrangement of the resistors does not affect their electrical relationship; what matters is how they are connected in the circuit. The parallel resistor equation, 1/Rtotal = 1/45 + 1/15, can be applied correctly in this scenario. Understanding the connections rather than the layout is crucial for solving circuit problems accurately.
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Homework Statement
Find the reading of the idealized ammeter if the battery has an internal resistance of 3.06 Ω
Relevant Equations
Series Equation:
1/R = 1/R1 +..... 1/Rn
I cannot understand why the 45 ohm resistor is parallel to the 15 ohm resistor. It's been defined that if two or more resistors are in parallel they same common connection points. I don't see these connections points. Is the junction point after the ammeter signifying that the 45 ohm and 15 ohm resistor are in parallel hence I can use the parallel resistor equation

1/Rtotal = 1/45 + 1/15.

I thought they where all in series but the answer was wrong.




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The connecting wires are deemed to have zero resistance, so the E shaped system of wires connecting the left sides of those two resistors and the left side of the battery are effectively a single point. Likewise the backward E on the right side.
 
In Parallel.png
I only moved the 15 Ω resistor from the bottom of the circuit diagram to the top. Does it look like it is in parallel with the 45 Ω resistor now?
 
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These are all the same circuit, with the same solution. What matters is how things are connected, not how they are located on the page.

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