Finding Partial Derivative of an Integral

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physman88
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Hey everyone. I am new here and i have a problem with some partials. We're studying partial derivatives in calculus III. I understand and all, but we haven't covered how to take a partial derivative of an integral. This problem showed up in my practice problems before our exam tomorrow.

The problem is as follows:

[tex]\frac{\partial}{\partial}x[/tex][tex]\int[/tex]cos(t[tex]^{3}[/tex])dt

If you can't follow that.. then it says we need the first partials (x and y) of the integral of cos(t^3)dt.. (lower limit=y, and upper limit=x)

Any insight on how to start this problem?? Thanks for any help!


-Kev
 
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physman88 said:
Hey everyone. I am new here and i have a problem with some partials. We're studying partial derivatives in calculus III. I understand and all, but we haven't covered how to take a partial derivative of an integral. This problem showed up in my practice problems before our exam tomorrow.

The problem is as follows:

[tex]\frac{\partial}{\partial}x[/tex][tex]\int[/tex]cos(t[tex]^{3}[/tex])dt

If you can't follow that.. then it says we need the first partials (x and y) of the integral of cos(t^3)dt.. (lower limit=y, and upper limit=x)

Any insight on how to start this problem?? Thanks for any help!


-Kev
I couldn't follow it because you didn't put in the limits of integration, and that is crucial!

You should know from single variable calculus, the "Fundamental Theorem of Calculus":
[tex]\frac{d}{dt}\int_a^x f(t)dt= f(x)[/tex]
where a is any constant.
From that it should be easy to find the partial derivative with respect to x.

To find the derivative with respect to y, remember that
[tex]\int_y^a f(t)dt= -\int_a^y f(t)dt[/tex]
 
I understand that you couldn't follow it, but may I ask how to get the limits on the integral? Sorry for the mix-up.
 
HallsofIvy...your d/dt should be a d/dx for the fund. theor... the way you have it written it would be zero