(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the point(s) on the graph of the function at which the tangent line has the indicated slope. (If an answer does not exist, enter DNE.)

g(x) = (1/3)x^3 - (1/2)x^2 - 4x +8

mtan=-4

2. Relevant equations

3. The attempt at a solution

firstly i derived g(x) to give x^2-x-4

as tangent line = -4 substituted into equation to give x^2-x-4=-4

manipulated to get x^2-x=0

that gave me x=0 or x=-1

used those values in original function to find y values

points i obtained were (0,8) and (-1,67/6)

when i enter these with lowest x value first it says i am wrong please help

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# Finding points on a tangent line

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