Finding polar form of complex number

[astrololo]

Homework Statement

I have the following complex numbers : -3,18 +4,19i
I must put it in polar form.

Homework Equations

r=(a^2+b^2)^(1/2)
cos x = a/r
sin x = b/r

The Attempt at a Solution

I was able to find with cos x = a/r that the x = 127,20

But when I do it with sin x = b/r I obtain like 52 degrees. I know that I Must obtain 127,20 for BOTH. Why isn't it working ?

 

[FactChecker]

The sin of both those angles are the same, so you must decide which is correct. That is the angle that has the correct a,b values. 52 degrees would be at (3.18, 4.19) and 127.2 degrees is at (-3.18, 4.19).

 

[astrololo]

The sin of both those angles are the same, so you must decide which is correct. That is the angle that has the correct a,b values. 52 degrees would be at (3.18, 4.19) and 127.2 degrees is at (-3.18, 4.19).

Oh ok so its normal that I obtain two different values. Ok then, thank you!

 

[HallsofIvy]

Yes, There are always two values of \theta in the interval 0 to 2\pi that have the same sin(\theta). But you still have to determine which is correct for the specific problem- the two different values, \theta have different values for cos(\theta).