Give the velocity v = ds/dt and initial position of a body moving along a coordinate line.
Find the body's position at time t.
v = 32t - 2, s(.5) = 4
The Attempt at a Solution
Here's how the solution manual does it:
step 1. v = ds/dt = 32T - 2
step 2. s = 16T^2 - 2T + C; at s = 4 and T = .5 (I understand this)
step 3. (find C)
C = 1 (I understand how to do that)
step 4. therefore
s = 6T^2 - 2T + 1
Why 6T^2? How did they get that. I don't understand.