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Finding position from velocity

  1. Jan 29, 2012 #1
    1. The problem statement, all variables and given/known data

    Give the velocity v = ds/dt and initial position of a body moving along a coordinate line.
    Find the body's position at time t.

    v = 32t - 2, s(.5) = 4


    3. The attempt at a solution

    Here's how the solution manual does it:

    step 1. v = ds/dt = 32T - 2

    step 2. s = 16T^2 - 2T + C; at s = 4 and T = .5 (I understand this)

    step 3. (find C)

    C = 1 (I understand how to do that)

    step 4. therefore

    s = 6T^2 - 2T + 1

    Why 6T^2? How did they get that. I don't understand.
     
  2. jcsd
  3. Jan 29, 2012 #2
    That looks like a typo on their part. The answer is 16t^2 - 2t + 1, as you originally got.
     
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