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Finding position from velocity

  • Thread starter bobsmith76
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  • #1
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Homework Statement



Give the velocity v = ds/dt and initial position of a body moving along a coordinate line.
Find the body's position at time t.

v = 32t - 2, s(.5) = 4


The Attempt at a Solution



Here's how the solution manual does it:

step 1. v = ds/dt = 32T - 2

step 2. s = 16T^2 - 2T + C; at s = 4 and T = .5 (I understand this)

step 3. (find C)

C = 1 (I understand how to do that)

step 4. therefore

s = 6T^2 - 2T + 1

Why 6T^2? How did they get that. I don't understand.
 

Answers and Replies

  • #2
166
0
...
step 4. therefore

s = 6T^2 - 2T + 1

Why 6T^2? How did they get that. I don't understand.
That looks like a typo on their part. The answer is 16t^2 - 2t + 1, as you originally got.
 

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