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Homework Statement
A generalized [itex]TdS[/itex]-equation for systems of several types of "work-parts" and varying number of particles in multiple components, is given by
[tex]dU = TdS + \sum_{i}y_idX_i+\sum_{\alpha =1}^{c}\mu_\alpha dN_{\alpha}[/tex]
Thus, its natural to regard the internal energy [itex]U[/itex] (an extensive property), as a function of the extensive variables [itex]U, S, {X_i}, {N_{\alpha}}.[/itex] Here [itex]U_\alpha[/itex] is the chemical potential for component [itex]\alpha[/itex], and [itex]N_\alpha[/itex] is the number of particles in component [itex]\alpha[/itex] of the system (a number that can vary by [itex]dN_\alpha \neq 0[/itex]). Thus we have
[tex]U = U(S, X_i, N_\alpha)[/tex]
Because [itex](U, S, X_i, N_\alpha)[/itex] are all extensive properties, we have the following homogeneity condition
[tex]U(\lambda S, \lambda {X_i}, \lambda {N_\alpha}) = \lambda U(S, {X_i}, {N_\alpha})[/tex]
Homework Equations
My question regards a special case of this, namely a one-component gass system (not an ideal gass!) with the following internal energy
[tex]U = U(S, V, N) = \frac{aS^3}{NV}[/tex]
where [itex]a[/itex] is a a constant with dimension [itex]K^3m^3/J^2[/itex].
Problem: find the pressure [itex]p[/itex], the temperature [itex]T[/itex] and the chemical potential [itex]\mu[/itex] of this gas expressed by [itex](S, V, N)[/itex]. And then find the heat capacities at constant volume [itex]C_V[/itex] and pressure [itex]C_p[/itex], expressed by [itex](N, T, V )[/itex] and [itex](N, T, p)[/itex], respectively.
The Attempt at a Solution
The [itex]TdS[/itex]-equation becomes
[tex]TdS = dU + pdV - \mu dN = C_vdT + \left[\left(\frac{\partial U}{\partial V}\right)_T + p\right]dV - \mu dN[/tex]
But here I am completely at a loss.