Thermodynamic equilibrium for systems only open to particle exchange

In summary: However, if you want to pursue this further, maybe you could look at a potential energy equation?Off hand, it is not clear to me the...relation between the chemical potential and the temperature. However, if you want to pursue this further, maybe you could look at a potential energy equation?
  • #1
EE18
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Homework Statement
I am working Callen Problem 3.4-13 which reads:
An impermeable, diathermal, and rigid partition divides a container into two subvolumes, each of volume ##V##. The subvolumes contam, respectively, one mole of H2 and three moles of Ne. The system is maintained at constant temperature ##T##. The partition is suddenly made permeable to H2, but not to Ne, and equilibrium is allowed to reestablish. Find the mole numbers and the pressures.
Relevant Equations
See below.
I am only interested in the initial equilibrium conditions, and I am struggling to convince myself whether that should correspond to the equality of chemical potentials for H2 or an equality of temperatures as well. My work is as below:

We take both gases as simple ideal (this is only relevant for later, and as mentioned no worries about this part). We could write ##dS## in terms of all of the possible ##dX_i## for extensive parameters ##X_i## which can be independently varied in a virtual process from the final constrained equilibrium, but it should be clear that the only possible parameters which can be varied are ##dU_A## and ##dN_{2,A}## (we let 1 denote Ne and 2 H\textsubscript{2} and ##A## and ##B## denote the two subvolumes) since ##dU_A = -dU_B## and ##dN_{2,A} = -dN_{2,B}## and the other parameters cannot vary. One further has, from conservation of energy, that in this constrained equilibrium the only possible virtual processes involve mass transfers so that we arrive at ##dU_A = \mu_{2,A}dN_{2,A}## (this is the chemical work noted in Chapter 1.8). Thus our equilibrium maximization condition is
$$0 = dS = \left(\frac{1}{T_A} - \frac{1}{T_B}\right)\mu_{2,A}dN_{2,A} + \left(\frac{\mu_{2,A}}{T_A} - \frac{\mu_{2,B}}{T_B}\right)dN_{2,A}$$
which, since ##dN_{2,A}## is arbitrary, implies that
$$ 0 =\left(\frac{1}{T_A} - \frac{1}{T_B}\right)\mu_{2,A} + \left(\frac{\mu_{2,A}}{T_A} - \frac{\mu_{2,B}}{T_B}\right) $$
But I can't go further than this. I can see that the equality of temperatures and chemical potentials is sufficient for this condition, but is it necessary?
 
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  • #2
Isn't the temperature T equal for the two chambers and constant over the process? Isn't the condition for equilibrium of H2 equal chemical potential in the two chambers? What is the equation for the chemical potential of an ideal gas component in a mixture?
 
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  • #3
Chestermiller said:
Isn't the temperature T equal for the two chambers and constant over the process? Isn't the condition for equilibrium of H2 equal chemical potential in the two chambers? What is the equation for the chemical potential of an ideal gas component in a mixture?
Oy, I completely skipped over the part about each subvolume being at ##T##, you are right. Can you comment incidentally on what would occur if not (as i thought was the case)? How does the condition I've arrived imply the equality of temperatures in that case?
 
  • #4
EE18 said:
Oy, I completely skipped over the part about each subvolume being at ##T##, you are right. Can you comment incidentally on what would occur if not (as i thought was the case)? How does the condition I've arrived imply the equality of temperatures in that case?
Please answer my questions first.
 
  • #5
Chestermiller said:
Please answer my questions first.
Isn't the temperature T equal for the two chambers and constant over the process?
Yes, equal initially.. It's actually not clear to me why it must necessarily remain so throughout the process (I know that ##U## is only a funciton of ##T## in an ideal gas, but there's nothing here which makes it clear a a priori that the temperatures in the subvolumes can't change as there's mass transfer, so perhaps my initial question stands)? Actually I see that the system is maintained at ##T##, so this is moot. But if it were an isolated system it would be interesting to think about.

Isn't the condition for equilibrium of H2 equal chemical potential in the two chambers?
I am trying to prove the relevant equilibrium. I agree that this is certainly the case if the connecting wall is not adiabatic. As I've shown here, it's not as clear if not. I think this is a similar sort of problem as Callen's adiabatic piston.

What is the equation for the chemical potential of an ideal gas component in a mixture?
I quote from an earlier problem I worked: Using the definition of the partial pressure ##P_j## from Problem 3.4.11, we can change the first term to be of the form below:
$$\mu_j := RT\ln \frac{P_jv_0}{RT} + f(T).$$
 
  • #6
EE18 said:
Isn't the temperature T equal for the two chambers and constant over the process?
Yes, equal initially.. It's actually not clear to me why it must necessarily remain so throughout the process (I know that ##U## is only a funciton of ##T## in an ideal gas, but there's nothing here which makes it clear a a priori that the temperatures in the subvolumes can't change as there's mass transfer, so perhaps my initial question stands)? Actually I see that the system is maintained at ##T##, so this is moot. But if it were an isolated system it would be interesting to think about.

Isn't the condition for equilibrium of H2 equal chemical potential in the two chambers?
I am trying to prove the relevant equilibrium. I agree that this is certainly the case if the connecting wall is not adiabatic. As I've shown here, it's not as clear if not. I think this is a similar sort of problem as Callen's adiabatic piston.
Off hand, it is not clear to me the conditions for equilibrium if the partition is adiabatic rather than diathermal. But clearly, as you correctly deduced, for diathermal, the condition is equal temperatures.
EE18 said:
What is the equation for the chemical potential of an ideal gas component in a mixture?
I quote from an earlier problem I worked: Using the definition of the partial pressure ##P_j## from Problem 3.4.11, we can change the first term to be of the form below:
$$\mu_j := RT\ln \frac{P_jv_0}{RT} + f(T).$$
The equation is $$\mu_j=\mu_j^0(T,P^0)+RT\ln{(p_j/P^0)}$$where ##P_0## is a reference pressure (typically 1 bar), ##\mu_j^0(T,P^0)## is the molar free energy of pure species j at T and P^0, and ##p_j## is the partial pressure of species j in the mixture (or pure). The condition of equilibrium is equal chemical potentials in the two chambers for H2, or, equivalently, equal partial pressures. So the pressure of H2 in the chamber with pure H2 must be equal to the partial pressure of the H2 in the chamber with the mixture of Ne and H2.
 
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What is thermodynamic equilibrium for systems only open to particle exchange?

Thermodynamic equilibrium for systems only open to particle exchange is a state where the exchange of particles between the system and its surroundings is balanced, and the system has reached a stable state with no net change in its macroscopic properties over time.

How is thermodynamic equilibrium achieved in systems open to particle exchange?

Thermodynamic equilibrium is achieved in systems open to particle exchange through the process of diffusion, where particles move from areas of high concentration to areas of low concentration until the concentration is equalized throughout the system.

What are the implications of thermodynamic equilibrium for systems open to particle exchange?

The implications of thermodynamic equilibrium for systems open to particle exchange include the fact that the system will remain in a state of constant macroscopic properties, and that any changes in the system will be balanced by an equal and opposite change in the surroundings.

How does thermodynamic equilibrium relate to the second law of thermodynamics?

Thermodynamic equilibrium is a state of maximum entropy, which is in accordance with the second law of thermodynamics. This law states that in a closed system, the total entropy will always increase over time until it reaches a maximum at thermodynamic equilibrium.

What factors can disrupt thermodynamic equilibrium in systems open to particle exchange?

Thermodynamic equilibrium in systems open to particle exchange can be disrupted by changes in temperature, pressure, or concentration gradients, which can cause a net flow of particles and result in a change in the system's macroscopic properties over time.

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