(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 3-litre vessel contains gas at a pressure of 200 kPa. Five litres of gas at the same pressure is forced into the vessel. Calculate the new pressure of the gas.

2. Relevant equations

P1V1 = P2V2

3. The attempt at a solution

P1V1 = P2V2 (Keeping Temp = Constant)

V2 = 3 + 5 = 8 litres

3 * 200 = P2 * 8

P2 = 600/8 = 75 kPa

I have been told this answer is wrong but unsure why if anyone could help me out, would greatly appreciate it.

Thanks, Joe

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# Finding Pressure with constant temperature and varying volume

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