Finding Qp for CO + 3H2 equilibrium at 773K

[tribalman100]

Homework Statement

The following amounts of substances are added to a 7.25 L reaction vessel at 773K:
(.103 mol CO) , (.205 mol H2), ( 2.1 mol CH4), ( 3.15 mol H20). In what direction will a net reaction occur to react equilibrium.

CO(g) + 3H2(g) --------> CH4(g) + H20 (g)
<-------

Kp= 102 at 773K

The answer to this problem is a slight net reaction occurs to the right because QP (98.4) is slightly less than Kp (102)

The problem i have is everytime i try to do the work i can't get the Qp to = 98.4

If someone will help me i will be very greatful

Homework Equations

The Attempt at a Solution

here is my attempt sry i forgot to post it

first i put all the moles in molarity and got the folloying
CO--- .42 M
H2--- .28
CH4--- .014
H2) --- 2x10-5 when you cube it cause of the coefficient

Then i put a Qp equation

Qp= ( .42)(.28)
--------------------
------( .014)(2e-5)

Final answer i got was Qp= 420000 way off i can't figure out why

 

[chemisttree]

The reaction quotient (Qp) in this case refers to the partial pressures of each of the species (rather than molarity). I believe the exponent for each of the partial pressures if given by the mole fraction of each species.