Finding Quadratic Approximation of ln(1.25) with Taylor Polynomial P2

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The discussion focuses on finding a quadratic approximation of the function f(x,y) = ln(x² + y²) at the point (1,0) using the Taylor polynomial P2. The calculated polynomial is P2(x,y) = y² - x² + 4x - 3. Participants explore values for x and y that satisfy the equation x² + y² = 1.25, with suggestions including (1.1, 0.2) for improved accuracy. However, achieving four decimal places of accuracy proves challenging, as even the simplest substitutions yield only two decimal places.

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Using P2(x,y), find a quadratic approximation to ln(1.25) to 4 decimal places.

The original function is f(x,y)=ln(x2 + y2) and is about the point (1,0).

I calculated P2 to be y2-x2+4x-3

however I don't know how to find a quadratic approximation. Do I just set say x=1 and y=.5?

Any help would be great!
 
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Thats not exactly it, but on the right track. Just any values of x and y that make x^2 + y^2 = 1.25. (1, 0.5) would work, but would not give you 4dp accuracy. Something like (1.1, 0.2) would work somewhat better, but still nowhere near 4dp accuracy.

EDIT: I don't know how they expect you to get 4dp accuracy, seeing as even x^2=1.25 and y=0 gives only 2dp accuracy. Sorry
 

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