Finding Ratios Using Mass Points in Triangles with Four Points

Click For Summary
SUMMARY

The discussion focuses on calculating the ratio EH:HG using mass points in a triangle configuration involving four points. The key method involves simplifying the problem by first analyzing triangle ABC and identifying the intersection point X of segments CG and DF. By breaking down the problem into manageable parts, specifically focusing on triangle CGD, the solution becomes clearer and avoids complications associated with handling all four points simultaneously.

PREREQUISITES
  • Understanding of mass points in geometry
  • Familiarity with triangle properties and segment intersections
  • Knowledge of trisection points in a triangle
  • Ability to visualize geometric configurations
NEXT STEPS
  • Study the application of mass points in complex geometric configurations
  • Learn about triangle similarity and its implications on ratios
  • Explore techniques for finding intersection points in geometric figures
  • Investigate advanced geometric problem-solving strategies
USEFUL FOR

Students studying geometry, particularly those tackling problems involving mass points and triangle ratios, as well as educators looking for effective teaching methods in geometric concepts.

soopo
Messages
222
Reaction score
0

Homework Statement



Find the ratio EH:HG. Please, see the full question with a picture here: https://dl.getdropbox.com/u/175588/problem.JPG

Homework Equations



"In triangle ABC, let D and E be the trisection points of BC with D between B and E." Please, see the full question with a picture here: https://dl.getdropbox.com/u/175588/problem.JPG

The Attempt at a Solution



I am unable to calculate mass points to a line with four mass points.
 
Last edited by a moderator:
Physics news on Phys.org
First draw in CG and deal with triangle ABC with segments CG and DF which intersect at a point, call it X. Find the location of X.

Then deal with triangle CGD.

This way you avoid dealing with "four all at once."
 
Billy Bob said:
First draw in CG and deal with triangle ABC with segments CG and DF which intersect at a point, call it X. Find the location of X.

Then deal with triangle CGD.

This way you avoid dealing with "four all at once."

So if we can serve one point in only one way, we are done. The point could also be served by other triangles but we must stick to the one we choose, just like you choose consider CDG.

Thank you for your answer!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
15
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K