Finding Re (α + α^2 + α^3 + α^4 + α^5)

  • Thread starter Thread starter NEILS BOHR
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on calculating the real part of the expression Re(α + α² + α³ + α⁴ + α⁵), where α = e^(i8π/11). The user successfully simplifies the expression to α(α⁵ - 1) / (α - 1). The suggestion to utilize Euler's formula, e^(ix) = cos(x) + i sin(x), is presented as a method to further simplify and solve the problem. This approach is essential for extracting the real component of the complex expression.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with Euler's formula
  • Basic knowledge of algebraic manipulation of expressions
  • Concept of real and imaginary parts of complex numbers
NEXT STEPS
  • Study the application of Euler's formula in complex number calculations
  • Learn about the geometric interpretation of complex numbers on the unit circle
  • Explore the properties of roots of unity in complex analysis
  • Investigate methods for simplifying complex expressions in algebra
USEFUL FOR

Students studying complex analysis, mathematicians working with trigonometric identities, and anyone interested in solving problems involving complex numbers and their real components.

NEILS BOHR
Messages
79
Reaction score
0

Homework Statement


Let alpha = e ^ i8pi / 11 , then find Re ( alpha + alpha ^2 + alpha ^3 + alpha ^4 + alpha ^5).


Homework Equations





The Attempt at a Solution


look i have reduced the expression to \alpha (\alpha^5 -1 ) / \alpha-1

now what to do??:confused:
 
Physics news on Phys.org
Have you tried using Euler's formula:
e^ix = cosx + isinx
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
8
Views
2K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K