I've been have having difficulties finding the roots of this:
Find the roots of 3ix^2 + 6x - i = 0
where i = complex number
i = sqrt(-1)
quadratic formula (apologies for the large image)
The Attempt at a Solution
using the quadratic formula
[-6 (+-) sqrt (36 - 4(3i)i)] / 6i
= (-6/6i) + (sqrt(24)/6i)
multiplying by conjugate I get:
=i (+-) ((-6i * sqrt(24))/ 36)
I'm stuck here.
apparently the roots should have both real and imaginary parts, but I have 2 imaginary parts. ie x = Re + i Im
what exactly do I have to do next?