A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in Figure A, she rotates about her center of mass at a rate of 6.03 rad/s. Her moment of inertia about this axis is 16.1 kg·m2. A short time later the aerialist is in the straight position, as shown in Figure B. If the moment of inertia about her center of mass in this position is now 33.1 kg·m2, what is her rotational speed?
KE=.5*m*v^2 w(omega)= v/r
The Attempt at a Solution
I've been struggling with this course all year. This is my first physics course outside of college. My biggest problem is that my professor mainly does derivation in class. Once its time for homework were we are using values instead of variables I freeze up. Any help is really appreciated. I just need a nudge in the right directions to start this problem.