Finding Slope with Desmos and Table

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    Desmos Slope Table
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Discussion Overview

The discussion centers around finding the slope of a secant line using Desmos and whether it is possible to display these slopes in a third column in a table. The context involves mathematical reasoning related to slopes and derivatives.

Discussion Character

  • Mathematical reasoning, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions the necessity of using Desmos for calculating slopes, suggesting that it can be done easily with calculus.
  • Another participant expresses a desire to use Desmos for its visual appeal, indicating a preference for technology in the calculation process.
  • A participant clarifies that the problem specifically asks for the slope of the secant line between two points, providing calculations for specific values of x and the corresponding slopes.
  • The calculations provided include specific examples for x=0 and x=0.4, with detailed slope results for each case.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the necessity of using Desmos versus manual calculations, and there is a disagreement regarding the relevance of derivatives in the context of the secant line problem.

Contextual Notes

The discussion includes assumptions about the definitions of slopes and secant lines, and the relevance of derivatives is questioned but not resolved.

karush
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2020_08_21_12.11.34~2.jpg

ok attemped to do this desmos but was sondering if there is away to get these slope in a 3rd column in the table with $m=\dfrac{\delta y}{\delta x}$

Screenshot 2020-08-21 at 2.01.04 PM.png
 
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Do you need to use Desmos? It's easy enough to calculate: [math]\dfrac{d(sec(x)}{dx} = tan(x)~sec(x)[/math]

-Dan
 
I just thot it would be cute if I did,,
 
How is the derivative relevant at all? The problem does not ask for the slope of the tangent line, it asks for the slope of the "secant" line, through P= (0.5, 0) and $Q= (x, cos(\pi x))$ for various values of x.

For (i) x= 0 so Q= (0, 1) and the slope of the slope of the secant line is $\frac{0- 1}{0.5- 0}= -2$. For (ii) x= 0.4 so Q=(0.4, 0.9998) so the slope of the secant line is $\frac{0- 0.9998}{.5- .4}= -9.998$ (to three decimal places).

What do you get for the others?
 

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