Finding Solution to 2nd Order Diff Eq at x=1

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SUMMARY

The solution to the second-order differential equation y'' = 10y - 200 at x = 1 is confirmed to be y = 29.91152764, derived from the general solution y = A exp{(10)^0.5 x} + B exp{- (10)^0.5 x} + 20, with coefficients A = 0.276701988 and B = 79.72329801. The particular integral is correctly identified as 20. MATLAB calculations corroborate the solution, yielding a value of 25.7312811548222 at x = 1, which can be verified by substituting back into the original equation.

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Homework Statement


Find the solution to the following 2nd Order Differential Equation at x = 1:
y'' = 10y -200

Boundary conditions:
when x = 0, y = 100
when x = 1, y' = 10

2. The attempt at a solution
Complimentary function: y = A exp{(10)^0.5 x} + B exp{- (10)^0.5 x}
Particular Integral: 20
General Solution: y = A exp{(10)^0.5 x} + B exp{- (10)^0.5 x} + 20
Coefficients: A = 0.276701988 B = 79.72329801
At x = 1, y = 29.91152764

My concern is whether the P.I. is correct.
P.S. I ran this diff equation in MATLAB and the solution at x = 1 was calculated to be 25.7312811548222.
 
Last edited:
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Yes, it is. It's easy enough to check for yourself. Just plug it back to see if it satisfies the differential equation.
 

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