Finding Solutions for Second Order ODE with Initial Condition y(0)=6

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SUMMARY

The discussion centers on the second order ordinary differential equation (ODE) given by y'' + t²*y = 0 with the initial condition y(0) = 6. It is established that infinitely many functions satisfy this equation due to the lack of a second initial condition for y', which is necessary for a unique solution according to the existence and uniqueness theorem. The conclusion confirms that varying y'(0) will yield valid solutions, thus reinforcing the notion of multiple solutions.

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Homework Statement



How many functions y(t) satisfy both y''+t^2*y=0 and y(0)=6?

2. The attempt at a solution

As this is a second order differential equation, two initial conditions (for y and y') would be needed to obtain a unique solution (cf. existence and uniqueness theorem). So the answer is 'infinitely many functions' as we are given only y(0)=6. Have I understood it correctly?
 
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As long as all those different y'(0) lead to valid solutions, that works.
 
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mfb said:
As long as all those different y'(0) lead to valid solutions, that works.

Oh, OK. Many thanks. :)
 

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