Finding Spring with kinetic friction involved

  • Thread starter mtsac
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  • #1
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Hello everyone, i have the following two part prompt and im having a difficult time with the second part. Here is first part of the prompt,

A block of mass 0.528 kg slides with uniform velocity of 4.15 m/s on a horizontal frictionless surface. At some point, it strikes a horizontal spring in equilibrium. If the spring constant is k = 25.5 N/m, by how much will the spring be compressed by the time the block comes to rest?

I found the spring compression to be 0.59m using Energy(initial)+Work(non conserved)= Energy(Final)

The second part is as follows,

What is the amount of compression if the surface is rough under the spring, with coefficient of kinetic friction µk = 0.411?

From what i learned in class i am supposed to stick to the concept used above, so I plugged in Kinetic friction for work as '-0.411d'. My professor made it known that d stood for the distance but I'm not sure where I can pull that information.

I tried using 0.59 since that 'was' the distance travelled before friction was introduced but it didn't work out.

Any help would be appreciated.
 

Answers and Replies

  • #2
Doc Al
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From what i learned in class i am supposed to stick to the concept used above, so I plugged in Kinetic friction for work as '-0.411d'.
Your expression for the work done by friction is incorrect. Given the coefficient of friction, what's the force of friction?
My professor made it known that d stood for the distance but I'm not sure where I can pull that information.
You're going to solve for the distance, so set up an energy equation with d as the unknown.
 

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