Finding Sup and Inf in Real Analysis: x^2 - 5x + 6 < 0 and x^2 + 1 = 0

  • Thread starter Thread starter converting1
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on finding the supremum (sup) and infimum (inf) of specific sets defined by inequalities and equations in real analysis. For the set { x | x^2 - 5x + 6 < 0 }, the infimum is 2 and the supremum is 3. The second set, { x^2 - 5x + 6 | x ∈ ℝ }, has an infimum of -1/4 and no supremum, as it is unbounded above. The third set, { x | x^2 + 1 = 0 }, has neither an infimum nor a supremum since there are no real solutions to the equation.

PREREQUISITES
  • Understanding of real analysis concepts
  • Familiarity with inequalities and their graphical representations
  • Knowledge of the properties of quadratic functions
  • Basic understanding of supremum and infimum definitions
NEXT STEPS
  • Study the properties of quadratic functions and their graphs
  • Learn about the concept of bounded and unbounded sets in real analysis
  • Explore the definitions and examples of supremum and infimum in various contexts
  • Investigate the use of TeX for mathematical notation and formatting
USEFUL FOR

Students in real analysis, mathematics educators, and anyone interested in understanding the concepts of supremum and infimum in mathematical sets.

converting1
Messages
65
Reaction score
0
find the sup and inf of the following sets:

{ x | x^2 - 5x + 6 &lt; 0 }

I got the inf and sup to be 2 and 3 respectively

{ x^2 - 5x + 6 | x \in ℝ}
here I was rather confused what this is saying. I'm assuming it's taking about the graph x^2 - 5x + 6 and assumed this was between [-1/4, ∞] so inf = -1/4 and sup does not exist as it is not bounded from above.

{x | x^2 + 1 = 0 }
as I'm in a real analysis class, there isn't a real number such that x^2 + 1 = 0, so inf and sup do not exist

could anyone check my answers and if my reasoning is correct, especially for the second one please

I don't understand why the curly brackets are not showing, but there should be curly brackets around all above in tex
 
Physics news on Phys.org
converting1 said:
find the sup and inf of the following sets:

\{ x | x^2 - 5x + 6 &lt; 0 \}

I got the inf and sup to be 2 and 3 respectively

Looks good.

{ x^2 - 5x + 6 | x \in ℝ}
here I was rather confused what this is saying. I'm assuming it's taking about the graph x^2 - 5x + 6 and assumed this was between [-1/4, ∞] so inf = -1/4 and sup does not exist as it is not bounded from above.

It's talking about the range, so yes, that looks right too.

{x | x^2 + 1 = 0 }
as I'm in a real analysis class, there isn't a real number such that x^2 + 1 = 0, so inf and sup do not exist

could anyone check my answers and if my reasoning is correct, especially for the second one please

I don't understand why the curly brackets are not showing, but there should be curly brackets around all above in tex

The curly brackets have a special use in TeX, so to display then you use \{ and \} as I did editing your first set.
 
LCKurtz said:
Looks good.



It's talking about the range, so yes, that looks right too.



The curly brackets have a special use in TeX, so to display then you use \{ and \} as I did editing your first set.

thank you for a fast reply,

is the last one correct too as you did not comment on that?
 
converting1 said:
thank you for a fast reply,

is the last one correct too as you did not comment on that?

I would say so as long as your text doesn't have some special convention for empty sets.
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
11
Views
2K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K