Equations of Parallel Tangent Lines to f(x)=3x(5x^2+1)

Click For Summary

Homework Help Overview

The discussion revolves around finding the equations of tangent lines to the function f(x)=3x(5x^2+1) that are parallel to the line y=8x+9. Participants explore the calculations related to the derivative of the function and the conditions for parallelism.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the derivative of the function and set it equal to the slope of the given line to find points of tangency. Some participants question the accuracy of the derivative calculation and suggest verifying results by substituting values back into the original function.

Discussion Status

Participants are engaged in verifying the calculations and discussing the importance of checking work. There is acknowledgment of the original poster's uncertainty about their final statements, and some guidance is offered regarding the verification process.

Contextual Notes

There is mention of the original poster's lack of confidence in their answers and their struggle with conveying thoughts clearly in writing. This context adds a personal dimension to the mathematical discussion.

Physics345
Messages
250
Reaction score
23

Homework Statement



Determine the equations of the tangent lines to the graph of f(x)=3x(5x^2+1) that are parallel to the line y=8x+9

Homework Equations


y=m(x-x_1 )+y_1

The Attempt at a Solution



11.f(x)=3x(5x^2+1)
The slope of the tangent line y=8x+9
f^' (x)=3(5x^2+1)+3x(10x)
f^' (x)=15x^2+30x^2+3
f^' (x)=45x^2+3
Finding the point of tangency:
m=8
8=45x^2+3
5=45x^2
√(x^2 )=√(45/5)
x=±1/3
f(1/3)=(3(1/3))(5(1/3)^2+1)
f(1/3)=1(5(1/9)+1)
f(1/3)=5/9+9/9=14/9
f(1/3)=14/9

f(-1/3)=(3(-1/3))(5(-1/3)^2+1)
f(-1/3)=-1(5(1/9)+9/9)
f(-1/3)=-1(5/9+9/9)
f(-1/3)=-14/9



y=m(x-x_1 )+y_1
y_1=14/9 x_1=1/3 m=8
y=8(x-1/3)+14/9
y=8x-8/3+14/9
y=8x-24/9+14/9
y=8x-10/9

y=m(x-x_1 )+y_1
y_1=-14/9 x_1=-1/3 m=8
y=8(x-(-1/3))-14/9
y=8x+8/3-14/9
y=8x+24/9-14/9
y=8x+10/9
Therefore, the equations of the tangent lines are y=8x+10/9 and y=8x-10/9 I'm pretty sure I did this correctly, but I'm not confident in my final statement.
 
Physics news on Phys.org
You seem correct.
 
  • Like
Likes   Reactions: Physics345
It looks good to me. After all those calculations, it's good to plug numbers back in and make sure it works as advertised: At x=1/3, does f' = 8 and f(x) = 3x(5x^2+1) = 8x+10/9? Do the same type of checks for x=-1/3.
 
  • Like
Likes   Reactions: Physics345
FactChecker said:
It looks good to me. After all those calculations, it's good to plug numbers back in and make sure it works as advertised: At x=1/3, does f' = 8 and f(x) = 3x(5x^2+1) = 8x+10/9? Do the same type of checks for x=-1/3.
Of course, I did that on paper, but I thought it would be pointless, to show to the teacher when I handed in my work. Especially since my teacher understands my enjoyment and capabilities when it comes to math. Thanks guys, I appreciate your advice.
 
  • Like
Likes   Reactions: lekh2003
You said that you were not confident in your answers. Plugging the numbers back into verify that the answers are correct should have given you confidence.

The one exception is in the slope of 8, which depends on whether you calculated the derivative correctly. That is hard to verify by plugging numbers directly into f(x) except by plugging in x=1/3 and something like x+Δx = 1/3+0.001.
 
  • Like
Likes   Reactions: Physics345
Plugging in numbers back again is a very fast way to figure out whether your answer is right, especially under time-intensive conditions or when the actual working is so long that you need an alternative method rather than skimming the working.

I just today used the technique of plugging the numbers back into the start in a long time-intensive financial math test, where most of the working is hidden in the calculator.
 
FactChecker said:
You said that you were not confident in your answers. Plugging the numbers back into verify that the answers are correct should have given you confidence.

The one exception is in the slope of 8, which depends on whether you calculated the derivative correctly. That is hard to verify by plugging numbers directly into f(x) except by plugging in x=1/3 and something like x+Δx = 1/3+0.001.
Oh I was referring to my therefore statement when I said that sir, and when I said "I'm pretty sure I did this correctly" I was referring to the math and using "pretty sure" was my scapegoat in case my math was somehow wrong in a way beyond, my spectrum of understanding. Sorry for the confusion! I have a problem conveying my thoughts through writing, it's something I've been working on a lot lately.
 
Last edited:
lekh2003 said:
Plugging in numbers back again is a very fast way to figure out whether your answer is right, especially under time-intensive conditions or when the actual working is so long that you need an alternative method rather than skimming the working.

I just today used the technique of plugging the numbers back into the start in a long time-intensive financial math test, where most of the working is hidden in the calculator.
Yes of course, I completely agree. The number one rule of doing math is checking your work, since there is always a way to do it in algebraically when it comes to functions, and by "always" I mean in relation to my current level of math.
 
Physics345 said:
Sorry for the confusion! I have a problem conveying my thoughts through writing, it's something I've been working on a lot lately.
Ha! I can really understand that! Being able to write clearly is something I have struggled with all my life. It's very good that you recognize how important that is.
 
  • Like
Likes   Reactions: Physics345
  • #10
FactChecker said:
Ha! I can really understand that! Being able to write clearly is something I have struggled with all my life. It's very good that you recognize how important that is.
Oh, I've always had this problem as well, unless I spend endless hours reviewing/refining what I write. I wish there was a easier solution, but I tend to rush into things without thinking, which I have found extremely hard to stop. Do you have any techniques or advice that could possibly help me out? I honestly thought I was crazy and this wasn't normal, I'm glad I found someone that can relate to my problem.
 
  • #11
Physics345 said:
Oh, I've always had this problem as well, unless I spend endless hours reviewing/refining what I write. I wish there was a easier solution, but I tend to rush into things without thinking, which I have found extremely hard to stop. Do you have any techniques or advice that could possibly help me out? I honestly thought I was crazy and this wasn't normal, I'm glad I found someone that can relate to my problem.
Just keep word-smithing your work to make it clearer. Eventually I learned what bad habits I have and look to correct those. I usually have to break up very long sentences and replace ambiguous pronouns with the specific nouns.
 
  • Like
Likes   Reactions: Physics345
  • #12
FactChecker said:
Just keep word-smithing your work to make it clearer. Eventually I learned what bad habits I have and look to correct those. I usually have to break up very long sentences and replace ambiguous pronouns with the specific nouns.
That's what I've been doing for a while now, it just takes a very long time. I guess eventually I'll be able to speed up the process with practice and time.
 

Similar threads

Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K