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Hey, I was needing some help with a friction problem involving finding the acceleration of an object.

I tried adding up all the forces in the X direction but I am still missing something. I know that the sum of the X forces is 44.8, and that the acceleration is .894 m/s², but I am not sure how the sum of the X forces is 44.8. Does the angle being below the horizontal have anything to do with it?

cos(26) = .899

sin(26) = .438

Fx = 250 N

Coefficient of Kinetic Friction = .300

**A 50.0-kg box is being pushed along a horizontal surface by a force of 250 N directed 26 degrees below the horizontal. The coefficient of kinetic friction between the box and the surface is 0.300. What is the acceleration of the box?**I tried adding up all the forces in the X direction but I am still missing something. I know that the sum of the X forces is 44.8, and that the acceleration is .894 m/s², but I am not sure how the sum of the X forces is 44.8. Does the angle being below the horizontal have anything to do with it?

cos(26) = .899

sin(26) = .438

Fx = 250 N

Coefficient of Kinetic Friction = .300

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