Finding the Angle Between Two Forces

  • Thread starter Thread starter Astrum
  • Start date Start date
  • Tags Tags
    Angle Forces
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 3K views
Astrum
Messages
269
Reaction score
5

Homework Statement


Question is in the attachment


Homework Equations





The Attempt at a Solution



I understand the concept and ideas, but the geometry evades me.

In polar coordinates, we have two components, [itex]\hat{r},\hat{\theta}[/itex]

I know that you just integrate the dot product of [itex]\vec{F}[/itex] and [itex]d\vec{r}[/itex] with the boundaries of position, but how did we find the angle between the two vectors?!

:confused:
 

Attachments

  • Untitled.png
    Untitled.png
    28.6 KB · Views: 560
Physics news on Phys.org
Question is in the attachment
... the question in the attachment is:
"What is the velocity of m when the rod is at angle ##\phi##?"
... which is answered in the rest of the attachment.

The geometry is circular. They drew you a diagram.
Probably what you need to do is redraw the diagram, bigger, for different values of ##\phi## - carefully draw in the vectors, resolve components, and watch how they change.
 
Simon Bridge said:
... the question in the attachment is:
"What is the velocity of m when the rod is at angle ##\phi##?"
... which is answered in the rest of the attachment.

The geometry is circular. They drew you a diagram.
Probably what you need to do is redraw the diagram, bigger, for different values of ##\phi## - carefully draw in the vectors, resolve components, and watch how they change.

I should have been clearer. I know the concept behind the problem, I know how they solved, just not where they go the [tex]cos(\varphi-\frac{\pi}{2}[itex] <br /> That perplexes me. The dot product equals the magnitude of each vector multiplied by each other, times the cos of the angle between them. <br /> <br /> I don't know how they determined the angle.[/itex][/tex]
 
Astrum said:
how did we find the angle between the two vectors?!

Can you show that the two angles marked θ in the picture are equal? [EDIT: The dotted line is horizontal]
 

Attachments

  • Pend angle.jpg
    Pend angle.jpg
    6.5 KB · Views: 492
Astrum said:
I should have been clearer. I know the concept behind the problem, I know how they solved, just not where they go the [tex]cos(\varphi-\frac{\pi}{2} )[/tex]

That perplexes me. The dot product equals the magnitude of each vector multiplied by each other, times the cos of the angle between them.

I don't know how they determined the angle.
... that is why I suggested you draw out the bigger diagrams. The exercise of resolving components gets you focussed on how the angles are related to each other. TSny has done one for you.
 
I didn't even realize that those angles were equal...

I have not a clue how to prove they're equal.