A dive bomber has a velocity of 275 m/s at an angle θ below the horizontal. When the altitude of the aircraft is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of the displacement from the point of release of the bomb to the target is 3.35 km. Find the angle θ?
The Attempt at a Solution
I have tried this like 6 different ways and they are all wrong. I'm confused if they want the instal angle or the angle form the bomb so Please help me.