1. The problem statement, all variables and given/known data A dive-bomber has a velocity of 230 m/s at an angle θ below the horizontal. When the altitude of the aircraft is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of the displacement from the point of release of the bomb to the target is 3.30 km. Find the angle θ. 2. Relevant equations xf=xi+1/2(vxi +vxf)*t xf=xi+vxi*t+1/2a*t2 vxf2= vxi2+2*a(xf-xi) vf = vi + a*t vxi= vi*cos(θ) vyi= vi*sin(θ) h= vi2*sin2 (θ)/(2g), g= gravity constant 9.8 m/s2, h= max height R= vi2*sin(2θ)/g, R=max horizontal range 3. The attempt at a solution I tried to do this by creating a triangle and using angle laws to find θ, where I did θ=tan-1(2.15/3.30), but thats wrong. I just cant visualize how to start this problem. If someone can just give me a hint on starting the problem, then maybe i can attempt to get a solution. I need help asap! Thanks!