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## Homework Statement

A clock pendulum oscillates at a frequency of 1.5 Hz. At t = 0, it is released from rest starting at an angle of 20° to the vertical. Ignoring friction, what will be the position (angle) of the pendulum at the following times? (Hint: Do not confuse the angle of swing θ of the pendulum with the angle that appears as the argument of the cosine.)

Find the angle at t = 0.25 s

## Homework Equations

T=1/f x=Acos(2pit/T) feta=2pi(t/T)

## The Attempt at a Solution

T=1/1.5 T=.67sec feta=2pi(.25sec/.67)