Finding the angle of projection and its speed in 2D Kinetics

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Homework Help Overview

The problem involves determining the angle of projection and speed of a projectile based on its trajectory described by the equation y = √3 x - (1/5)x². The context is rooted in 2D kinetics and involves calculus and projectile motion concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants express difficulty in starting the problem and request guidance. Some suggest considering the derivative dy/dx to find the angle of projection, while others inquire about the formula for range and its application. There are questions about the specific point at which to evaluate the gradient of the trajectory.

Discussion Status

The discussion is ongoing, with hints and partial formulas being shared. Participants are exploring different interpretations of the problem and attempting to clarify concepts related to the trajectory and its properties. There is no explicit consensus yet, but some productive lines of inquiry are emerging.

Contextual Notes

Participants are navigating assumptions about the trajectory's characteristics and the implications of the given equation. There is a request for clarification on the working steps and the relationship between the trajectory and the angle of projection.

dahano
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Homework Statement

: The trajectory of a projectile in a vertical plane is y = √3 x - (1/5)x2, where x and y are respectively horizontal and vertical distances of the projectile from the point of projection. Find the angle of projection and speed of projection.[/B]

Homework Equations

: 2-Dimensional Equations and maybe calculus.[/B]

The Attempt at a Solution

: Honestly, I can't even understand that how do I begin with this question. I've tried some wild attempts but they landed me no where :-( Can you please guide me with the solution to this question? [/B]
 
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dahano said:
I've tried some wild attempts but they landed me no where :-

Please post these attempts .

However I still give a hint :

What does dy/dx represent ?
What is the formula for Range ?
 
The angle of projection can be found from the gradient of the graph at what point?
 
I figured out the formula for Ran
Qwertywerty said:
Please post these attempts .

However I still give a hint :

What does dy/dx represent ?
What is the formula for Range ?

I figured out the formula of range as: u2Sin2(theta)/g

Can you tell me that how would it be done further?
 
andrevdh said:
The angle of projection can be found from the gradient of the graph at what point?
Sorry to ask a stupid question but what do you mean by point? Can you please show me how would it be solved?
 
dahano said:
I figured out the formula of range as: u2Sin2(theta)/g

Can you tell me that how would it be done further?

Here - dy/dx at x = 0 represents tan(θ) ( where θ is angle of projection ) .

Find range , and then using formula for range find u .
 
Last edited:
What does the trajectory or path of the projectile look like?
What is the equation which describes the path or trajectory?
 
dahano said:
I figured out the formula of range as: u2Sin2(theta)/g
Please attach your working for this.
 

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